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Implement a method 'find' that will find the starting index (zero based) where the second list occurs as a sub-list in the first list. It should return -1 if the sub-list cannot be found. Arguments are always given, not empty. Sample Input 1 list1 = (1, 2, 3) list2 = (2, 3) Sample Output 1 1 Explanation As second list (2, 3) is sub-list in first list (1, 2, 3) at index 1 Sample Input 2 list1 = (1, 2, 3) list2 = (3, 2) Sample Output 2 -1
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Senior Java Developer

Interviewed at Atlassian

3.2
Apr 13, 2016

Implement a method 'find' that will find the starting index (zero based) where the second list occurs as a sub-list in the first list. It should return -1 if the sub-list cannot be found. Arguments are always given, not empty. Sample Input 1 list1 = (1, 2, 3) list2 = (2, 3) Sample Output 1 1 Explanation As second list (2, 3) is sub-list in first list (1, 2, 3) at index 1 Sample Input 2 list1 = (1, 2, 3) list2 = (3, 2) Sample Output 2 -1

The first question is two find the largest and second largest value at each level of a binary tree. You don't need to return all values, just print out instead. the second question is to return a value in an array with the probability proportional to the weight of the value within the array. For example, in an array [4,5,6], return 4 with probability 4/15, 5 with 5/15 and 6 with 6/15. You are given a function that returns a random real number between 0 and 1
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Software Engineer

Interviewed at Meta

3.5
Nov 7, 2016

The first question is two find the largest and second largest value at each level of a binary tree. You don't need to return all values, just print out instead. the second question is to return a value in an array with the probability proportional to the weight of the value within the array. For example, in an array [4,5,6], return 4 with probability 4/15, 5 with 5/15 and 6 with 6/15. You are given a function that returns a random real number between 0 and 1

In most cases you need to have some experience with CUDA. If you want to increase your chances of getting a job offer you need to know very well about linked lists. We used the collabedit.com for the interview. It is like a chat but for coding. I got the following question on the screen of collabedit: // There is a chunk of memory in the kernel address space represented by kernelResource and an API exists to clear it. An IOCTL path exists to take a request from user-mode and using O/S services eventually dispatches to API_ZeroResource. From a security perspective what concerns do you have with this implementation? How would you fix them? // // KERNEL // BYTE kernelResource[10] = {0}; int API_ZeroResource( in_params *pParams ) { if (pParams->offset + pParams->length > sizeof(kernelResource)) return ERR_INVALID_LIMIT; memset(kernelResource + pParams->offset, 0, pParams->length); return 0; } // // USER // void ZeroResource() { in_params params = { ??? }; // an ioctl path exists to call API_ZeroResource ioctl( CMD_ZeroResource, &params ); }
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Software Engineer

Interviewed at NVIDIA

4.5
May 13, 2016

In most cases you need to have some experience with CUDA. If you want to increase your chances of getting a job offer you need to know very well about linked lists. We used the collabedit.com for the interview. It is like a chat but for coding. I got the following question on the screen of collabedit: // There is a chunk of memory in the kernel address space represented by kernelResource and an API exists to clear it. An IOCTL path exists to take a request from user-mode and using O/S services eventually dispatches to API_ZeroResource. From a security perspective what concerns do you have with this implementation? How would you fix them? // // KERNEL // BYTE kernelResource[10] = {0}; int API_ZeroResource( in_params *pParams ) { if (pParams->offset + pParams->length > sizeof(kernelResource)) return ERR_INVALID_LIMIT; memset(kernelResource + pParams->offset, 0, pParams->length); return 0; } // // USER // void ZeroResource() { in_params params = { ??? }; // an ioctl path exists to call API_ZeroResource ioctl( CMD_ZeroResource, &params ); }

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